2[t-(3t+19)+13]=2(t+6)

Solution for 2[t-(3t+19)+13]=2(t+6) equation:

Simplifying
2[t + -1(3t + 19) + 13] = 2(t + 6)

Reorder the terms:
2[t + -1(19 + 3t) + 13] = 2(t + 6)
2[t + (19 * -1 + 3t * -1) + 13] = 2(t + 6)
2[t + (-19 + -3t) + 13] = 2(t + 6)

Reorder the terms:
2[-19 + 13 + t + -3t] = 2(t + 6)

Combine like terms: -19 + 13 = -6
2[-6 + t + -3t] = 2(t + 6)

Combine like terms: t + -3t = -2t
2[-6 + -2t] = 2(t + 6)
[-6 * 2 + -2t * 2] = 2(t + 6)
[-12 + -4t] = 2(t + 6)

Reorder the terms:
-12 + -4t = 2(6 + t)
-12 + -4t = (6 * 2 + t * 2)
-12 + -4t = (12 + 2t)

Solving
-12 + -4t = 12 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-12 + -4t + -2t = 12 + 2t + -2t

Combine like terms: -4t + -2t = -6t
-12 + -6t = 12 + 2t + -2t

Combine like terms: 2t + -2t = 0
-12 + -6t = 12 + 0
-12 + -6t = 12

Add '12' to each side of the equation.
-12 + 12 + -6t = 12 + 12

Combine like terms: -12 + 12 = 0
0 + -6t = 12 + 12
-6t = 12 + 12

Combine like terms: 12 + 12 = 24
-6t = 24

Divide each side by '-6'.
t = -4

Simplifying
t = -4